How to get the directory of an indirect dependency

Tooling Package Management
1

I’m trying to write a script that analyzes all of the dependencies of a Julia project, including the indirect dependencies. I see how I can use pathof to get the path to the direct dependencies, but how can I do this for the indirect dependencies? Since they aren’t direct dependencies, they can’t be imported, so I can’t get access to the module to be able to pass it to pathof.

Thanks!

2

Not directly equivalent, since it will give you the project directory instead of the entrypoint file, but:

julia> for (uuid, info) in Pkg.dependencies()
           println("$(uuid) $(info.name) $(info.source)")
       end
29816b5a-b9ab-546f-933c-edad1886dfa8 LibSSH2_jll /home/david/.bin/julia-1.6.0/share/julia/stdlib/v1.6/LibSSH2_jll
4ec0a83e-493e-50e2-b9ac-8f72acf5a8f5 Unicode /home/david/.bin/julia-1.6.0/share/julia/stdlib/v1.6/Unicode
6462fe0b-24de-5631-8697-dd941f90decc Sockets /home/david/.bin/julia-1.6.0/share/julia/stdlib/v1.6/Sockets
ca575930-c2e3-43a9-ace4-1e988b2c1908 NetworkOptions /home/david/.bin/julia-1.6.0/share/julia/stdlib/v1.6/NetworkOptions
deac9b47-8bc7-5906-a0fe-35ac56dc84c0 LibCURL_jll /home/david/.bin/julia-1.6.0/share/julia/stdlib/v1.6/LibCURL_jll
bd369af6-aec1-5ad0-b16a-f7cc5008161c Tables /home/david/.julia/packages/Tables/UxLRG
...

More info here: 12. API Reference · Pkg.jl

Curious as to what analysis you are doing, if you can share :grin:

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3

I wanted to write a script to summarize the licenses of all of the dependencies, by looking for a LICENSE file in each package directory. I think your solution will do the trick, thanks!

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4

https://github.com/ericphanson/LicenseCheck.jl and https://github.com/JuliaEcosystem/PkgDeps.jl might be useful for that task (and maybe https://github.com/JuliaEcosystem/PackageAnalyzer.jl too).

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