julia> Type{Vararg} ERROR: TypeError: in Type, in parameter, expected Type, got Vararg this seems to be known and explicitly forced https://github.com/JuliaLang/julia/issues/30995 Does someone know an alternative way how I can dispatch on Vararg? I.e. I have a custom variable type which could be …

How to dispatch on Type Vararg?

tim.holy November 19, 2019, 10:14am 5

See the interfaces chapter for examples of methods that use Vararg dispatch.

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