How to convert a number to an hexadecimal `bitstring`?

General Usage
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1

I can do

string(parse(Int, bitstring(x), base=2), base=16)

to convert bitstring(x) to an hexadecimal string, but is there another way, one which is simpler and doesn’t trim the leading zeros off of integers?

2

Why are you calling bitstring at all and then parsing it? Why not just call string(x, base=16) directly? If you want leading zeros, you can use the pad parameter.

(You can also use @printf or @sprintf from the Printf stdlib, e.g. @sprintf("%010x", x) is similar to string(x, base=16, pad=10). @printf also allows you to output directly to an io stream without converting to a string first.)

3

Because x is a floating point number and as far as I understand string takes only integer values.

4

Just do n = reinterpret(UInt64, x) first (assuming x is a Float64). Of course, you can then just do repr(n) or show(n) directly to see a hex representation.

(In general, you should rarely have to go through a string form to convert between two non-string types.)

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