# How create constant list of integers

Suppose I have a given positive integer `n`. What are simple ways to create a list of length `n` consisting of all zeros exactly, that is, filled with the integer `0`?

For example, if `n` has value 5, then I want to create `[0, 0, 0, 0, 0]` but without explicitly entering five zeros.

`zeros(Int, n)` or `fill(0, n)`

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Does Julia have a replicate operator like the one in Python, where, for example, `[0] * 5` produces the list `[0, 0, 0, 0, 0]`?

``````repeat([0], 5)
``````
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`LinRange{Int}(0,0,n) `

OK, `repeat` in Julia works as does pythonâ€™s `*` replicate operator: it seems to apply generally, too â€“ to strings, matrices, etc. Thank you.

I personally donâ€™t think â€ś* by a scaler â†’ replicationâ€ť is very intuitive mathematically

Where is `*` documented? I have not been able to find it in the docs at julialang.org or through online search elsewhere.

@murrayE, for strings, `^` is a replicator in Julia:

``````julia> "Julia"^5
"JuliaJuliaJuliaJuliaJulia"
``````
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You also have `Tuple` or `ntuple(x->1,6)`

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hit `?` in REPL and type `*` then hit Enter:

``````help?> *
search: *

...
.....
``````

I think you should use `zeros` or `fill` rather than `repeat`. If you have a short list of constant length, known at compile time, you can consider a tuple or StaticArrays.jl.

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