How can I display all Float64 multidimensional arrays as vectors?

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#1

How can I display all Float64 multidimensional arrays as vectors? I tried the following but it stackoverflows:

Base.show(io::IO, x::Array{Float64}) = print(io, vec(x))

Probably it is running into a deadlock.

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#2

Something like this?

julia> a = rand(2,3,5)
2Ă—3Ă—5 Array{Float64,3}:
[:, :, 1] =
 0.593246  0.122574  0.77908
 0.959088  0.218372  0.0891396

[:, :, 2] =
 0.853314  0.171189  0.313323
 0.195373  0.342458  0.642057

[:, :, 3] =
 0.731841  0.951687  0.316416
 0.640172  0.230144  0.701338

[:, :, 4] =
 0.307028  0.172853  0.990212
 0.872871  0.79285   0.214958

[:, :, 5] =
 0.908459    0.441589  0.0691264
 0.00724457  0.371763  0.968289

julia> a[:]
30-element Array{Float64,1}:
 0.5932464540468072
 0.9590878214304634
 0.12257439090533429
 0.21837219429910104
 0.7790802711397888
 0.08913955642713955
 0.8533144973503481
 0.19537331243008405
 0.1711887305635067
 0.3424581504859132
 0.31332337994899184
 0.6420571681929719
 0.7318410592897324
 â‹®
 0.30702789473558245
 0.8728713274277637
 0.17285287148135597
 0.7928495776848725
 0.9902119213201215
 0.2149577614800653
 0.9084586968143415
 0.007244565168584183
 0.44158904493286766
 0.3717633735726962
 0.06912640765172728
 0.9682886566736622
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#3

It is not generally recommendable to rewrite the show method for arrays or other basic types (or any other method of functions from Base for types that you didn’t define – see the advice against “type piracy” in the manual). But let aside that, the specific problem in this case is that Array{Float64} includes Array{Float64, 1} (i.e. Vector{Float64}), so the method that you defined calls itself forever.

To make it work, you should also define:

Base.show(io::IO, x::Vector{Float64}) = print(io, x)
2 Likes
#4

I wasn’t aware of the advice against “type piracy”. I guess that the proper way is to make my own print function. Thank you very much.

1 Like