Get the name of a function in the argument

Usage First steps
,
#1

I would like to have a function that returns the name of the function in the argument, e.g.:

function give_me_my_name(f::Function)
    return ??? (f);
end

such that

give_me_my_name(sin)

returns

sin

as a string. How do I do that?

#2 
julia> function give_me_my_name(f::Function)
           return String(Symbol(f))
       end
give_me_my_name (generic function with 1 method)

julia> give_me_my_name(sin)
"sin"
3 Likes
#3 
julia> give_me_my_name(give_me_my_name)
"give_me_my_name"

:grin:

1 Like
#4

Awesome! Thanks!

The best about Julia is that brought child-like fun of programming back
to me — but a close second is that fantastic helpful & fun
Julia-Community!!! So cool!

#5

How do you do this for a mutable struct?

String(Symbol(X))

does not yield the name…

#6

Its just the same:

julia> mutable struct mutable_struct
       x
       end

julia> typeof(mutable_struct)
DataType

julia> function give_me_my_name(s::DataType)
           return String(Symbol(s))
           end
give_me_my_name (generic function with 2 methods)

julia> give_me_my_name(mutable_struct)
"mutable_struct"
#7

You can do it generic:

julia> function give_me_my_name(whatever)
           return String(Symbol(whatever))
           end
give_me_my_name (generic function with 3 methods)

julia> give_me_my_name(Int)
"Int64"
2 Likes
#8

Sorry, I explained myself badly: Variablenames
are only accessible by Macros, right? For

mutable struct mutable_struct
     x
     y
     z
end

var = mutable_struct(1,2,3);

function give_me_my_name(s::mutable_struct)
     return String(Symbol(s))
end

give_me_my_name(var)

I get "mutable_struct(1, 2, 3)" and for the macro, I have

macro give_me_my_name(s)
     String(s)
end
@give_me_my_name(var)

Or is that also possible in a function?

#9

No, I don’t think this is possible with a function. In the function it would be the function parameters name and not var anymore.