I would like to have a function that returns the name of the function in the argument, e.g.: function give_me_my_name(f::Function) return ??? (f); end such that give_me_my_name(sin) returns sin as a string. How do I do that?

julia> function give_me_my_name(f::Function) return String(Symbol(f)) end give_me_my_name (generic function with 1 method) julia> give_me_my_name(sin) "sin"

julia> give_me_my_name(give_me_my_name) "give_me_my_name" :grin:

Awesome! Thanks! The best about Julia is that brought child-like fun of programming back to me — but a close second is that fantastic helpful & fun Julia-Community!!! So cool!

How do you do this for a mutable struct? String(Symbol(X)) does not yield the name…

Its just the same: julia> mutable struct mutable_struct x end julia> typeof(mutable_struct) DataType julia> function give_me_my_name(s::DataType) return String(Symbol(s)) end give_me_my_name (generic function with 2 methods) julia> give_me_my_name(mutable_stru…

You can do it generic: julia> function give_me_my_name(whatever) return String(Symbol(whatever)) end give_me_my_name (generic function with 3 methods) julia> give_me_my_name(Int) "Int64"

Sorry, I explained myself badly: Variablenames are only accessible by Macros, right? For mutable struct mutable_struct x y z end var = mutable_struct(1,2,3); function give_me_my_name(s::mutable_struct) return String(Symbol(s)) end give_me_my_name(var) I get "mutable_struct(…

No, I don’t think this is possible with a function. In the function it would be the function parameters name and not var anymore.

You may find interesting this macro that prints the name of the current function it is called from: [image] How to print function name and source file/line number General Usage Hello, is it possible to print the current function name and the REPL/Juno/VSCode clickable fil…

It seems no one mentioned the built-in method Base.nameof . julia> function give_me_my_name(f::Function) return string(nameof(f)) end give_me_my_name (generic function with 1 method) julia> give_me_my_name(sin) "sin" It also works for a data type. julia> function give_me_my_name…

Get the name of a function in the argument

New to Julia

sylvaticus July 26, 2020, 7:46pm 10

You may find interesting this macro that prints the name of the current function it is called from:

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Get the name of a function in the argument

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