Get all Permutations of Array?

[Ahmed_Salih]

Hi

I found some old Julia code which states that this used to work:

Julia for MATLAB Users/Core Language/Mathematics - Wikibooks, open books for...

julia> perms(a) = reverse(collect(permutations(a)))
perms (generic function with 1 method)

julia> perms([2,4,6])
6-element Array{Array{Int64,1},1}:
 [6, 4, 2]
 [6, 2, 4]
 [4, 6, 2]
 [4, 2, 6]
 [2, 6, 4]
 [2, 4, 6]

But I cannot get this to work in Julia 1.5. Could anyone help out?

Kind regards

[Ahmed_Salih]

@Ahmed_Salih

permutations

Getting all possible combination of vector with all possible order

I know that there is combination function whthin package 'Combinatorics’ which gives me all possible combination without regarding order of elements x = combinations([1,2,3], 3) # which gives this collect(x) => [1,2,3] # but I couldn't find function for getting this. => [[1,2,3], [2,1,3], [3,1,2], [3,2,1]] I looked up “Combinatorics” and “Iterators” Packages, but couldn’t find function I need. thanks for your time.

Old thread stating similar code which does not work either anymore.

Kind regards

[Ahmed_Salih]

Found it!

JuliaMath/Combinatorics.jl

This package, and not “Permutations.jl” has the relevant function.

EDIT: A more performant solution is looking at “nthperm” and “nthperm!” in the same package. Especially if you want to generate it for arrays greater than 1x6