Get a view as type Array and not as type SubArray


#1

I have an array A of type Array{T, N}. I want a view of A but for various reasons I don’t want to deal with SubArray. Is there a way to get a view of A a la view(A, ...) but not as a SubArray but as Array{T, N}? I don’t mind if it is not as fast as a SubArray.


#2

You can’t generalize the function of your view to take AbstractArray{T,N}?
Why not take an actual slice instead of a view? Slicing returns an array.


#3

It is not about a function definition but about parametrized types. I don’t want another type parameter.

Slicing also returns a SubArray on julia 0.5 and an error for >= 0.6.

I don’t think it is possible to do what I want, but I wanted to make sure I am not missing something obvious.


#4

Slicing as in

a = rand(5)
b = a[1 : 3] # an Array{Float64,1}

not as in the old Base.slice.


#5

I don’t think it’s possible since Array doesn’t support general strides (as far as I know).

If you are taking a view of rows contained in a single column, it is possible using pointer arithmetic, but a very bad idea. Much better to just add another templates variable.