Hello, Say I have an alphabet of n symbols, and I want to generate all words of length k that can exist in that alphabet. What is the concise way to do that in Julia? I am expecting a list of n^k words. Writing k nested for loops looks a bit dull. This sounds something that should be a one-liner wi…

Iterators.product is actually already lazy. I collected it above since it sounded like that’s what OP wanted, but we can just as well iterate over it lazily: alphabet = 'a':'d' # or "abcd" k = 2 itr = Iterators.product(ntuple(_ -> alphabet, k)...) for word in Base.Generator(join, itr) println…

Generate all words of a given size from a fixed alphabet

General Usage

tanhevg February 19, 2019, 2:46pm 7

Thanks!

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Generate all words of a given size from a fixed alphabet

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