Hi, I’m trying to define a new function as follows: [Screenshot 2021-12-23 at 17.11.46] meaning, I’d like to integrate over x and y, leaving z as a variable. I thought maybe to integrate z over (0,z) and then differentiate the function with respect to z, but it seems to me quite intricate. Any ide…

Oh it’s giving you an SVector instead of two arguments, so it’s x[1] etc. You can write that all out, or use the simpler syntax h(z) = hcubature((x)->f(x…,z),…) to splat it

h(z) = hcubature((x,y)->f(x,y,z),…). It’s called a closure.

That’s interesting! I’m still learning Julia, so this is something new for me. Trying to implement this closure, I got the following method matching error: how can it be? Those #9#10 aren’t so clear to me [Screenshot 2021-12-23 at 17.45.09]

I love this syntax! Thank you a lot

Function defined as multidimensional integral

New to Julia

gustaphe December 23, 2021, 6:31pm 6

Welcome! For the future: please share code as text instead of images. Makes it easier to read, copy and run. You can use a triple backtick fence to get monospace font and syntax highlighting.

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Function defined as multidimensional integral

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