After a process usyng the SymPy in Julia, I generated a system of nonlinear equations. For the sake of simplicity, I am going to put an approximation here for the case of just a non-linear equation. What I get is something like this equation: R = (p) -> -5.0488*p + p^2.81 - 3.38/( p^(-1.0) )^2.0 I…

my function was written incorrectly, this runs without problem and finds a zero function R(F,p) #p is a vector too, not a number F[1] = -5.0488*p[1] + p[1]^2.81 - 3.38/( p[1]^(-1.0) )^2.0 end nlsolve(R , [5.8]) the results are: julia> nlsolve(R , [5.8]) Results of Nonlinear Solver Algorithm * Al…

Find zero of a nonlinear equation using Julia

General Usage

brett_knoss January 7, 2023, 12:47am 15

Ok, that makes sense. Is there an NL solver that can find imaginary numbers?

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Find zero of a nonlinear equation using Julia

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