Fastest way to parse a string of numbers

General Usage
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The Parsers.jl package is setup to handle these kind of parsing scenarios quite well. In this case, you can do something like:

parser = Parsers.Delimited(" "; ignorerepeated=true)
io = IOBuffer("1.0    2.34345              7.9")
Parsers.parse(parser, io, Float64) # returns 1.0
Parsers.parse(parser, io, Float64) # returns 2.34345
Parsers.parse(parser, io, Float64) # returns 7.9

It’s a bit tricky to benchmark because it relies on parsing from an IOBuffer, but it’s also very fast because it’s making exactly one pass over the strings in parsing all three numbers.

Let me know if you have any questions or concerns.

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