jtackm
1
I’m trying to use CSVFiles.jl to read a .tsv file that has a non-standard file extension (which cannot easily be changed).
The readme suggests
df = DataFrame(load(Stream(format"CSV", io)))
But trying to apply this pattern results in the following error:
path = "/file/tree/my_nonstandard_file.1b"
f = open(path)
df = load(Stream(format"CSV", f)) |> DataFrame
head(df)
What am I doing wrong here?
(By the way, I know there are alternatives (CSV.jl, DelimitedFiles etc.), but I would like to make CSVFiles work in this case)
( I am not tested )
but, based on the : https://github.com/queryverse/CSVFiles.jl/blob/master/test/runtests.jl#L128
can you test with
fileiostream = FileIO.Stream(FileIO.format"TSV", stream)
so with: format"TSV"
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jtackm
4
Unfortunately does not work either.
I see, then I’ll wait for the merge. Thanks!
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Can you try
using CSVFiles, DataFrames, FileIO
path = "/file/tree/my_nonstandard_file.1b"
df = load(File(format"TSV", path)) |> DataFrame
2 Likes
jtackm
6
Works like a charm! Maybe this could be reflected in the README.md of CSVfiles.
1 Like