Thank you it works perfectly !
If it helps anyone, to create a new dictionary without modifying the previous one I did this:
d2 = Dict(k =>(copy(d[k]) .= df2[df2 .== k, :Column2]) for k ∈ keys(d))
Thank you it works perfectly !
If it helps anyone, to create a new dictionary without modifying the previous one I did this:
d2 = Dict(k =>(copy(d[k]) .= df2[df2 .== k, :Column2]) for k ∈ keys(d))