I want to understand how in place functions are treatet when used like in this example function g!(u) u[:] .= 2*u[:] end u=[1] julia > g!(u) .*(u .+ g!(u)) 1-element Array{Int64,1}: 32 For my understanding, this is a completely awkward result. It seems, that the functions g are evaluate…

[image] MatFi: It seems, that the functions g are evaluated first Using prefix notation (and ignoring broadcasting for now) you have *(g(u), +(u, g(u))) so I wonder how you imagine that anything but the gs could be evaluated first — they are needed as inputs for both + and *. [image] Ma…

Calculus with in place functions

New to Julia

MatFi September 9, 2019, 9:29am 13

Indeed , good point…

I didn’t understand it as such either.

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Calculus with in place functions

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