For a struct with elements of the same type. Is there a way to broadcast operations over the elements, and create a new struct. Like you can for a Dictionary. struct X a::Float64 b::Float64 c::Float64 end x = X(1,2,3) x.^2 #X(1,4,9) a way to do this ? d = Dictionary([:a…

[image] Lincoln_Hannah: I wasn’t aware of Accessors.jl That’s a nice ability to modify existing or create a new struct. Accessors always create a new struct: it’s cleaner and often more performant. [image] Lincoln_Hannah: Can the below approach for multiplication be extended to more ope…

Couple ways: X( ( (getfield.(Ref(x), 1:fieldcount(X) )) .^ 2)...) X( ( (getfield.(Ref(x), fieldnames(X) )) .^ 2)...) [image] Lincoln_Hannah: d = Dictionary([:a,:b,:c],[1,2,3]) d.^2 dictionary ([:a,:b,:c],[1,4,9]) like this I’m not familiar with this dictionary type or this b…

Dictionaries.jl its pretty cool:)

Do you want the same struct back, but with modified fields? This kind of operation is what so-called “lenses” do, in Julia they are implemented in Accessors.jl composably and with a very nice interface. Your specific example, squaring all properties in x: julia> using Accessors julia> x X(1.0, 2.…

Thanks. I wasn’t aware of Accessors.jl That’s a nice ability to modify existing or create a new struct.

Can the below approach for multiplication be extended to more operations without writing each individually ? import Base.* struct X a::Float64 b::Float64 c::Float64 end X(x::Vector)=X(x...) ((;a,b,c)::X)() = [a,b,c] *(y::Number,x::X) = y * x() |> X *(x::X,y::Number) = y * x() |> X …

I don’t think it’s possible to write a definition for multiple operations at once because functions aren’t grouped together in any way besides subtyping Function, and you are not allowed to annotate a called instance with Function in a method definition. If that’s not true or there’s a workaround, s…

Depending what your original problem is, you might want to use LabelledArrays ( GitHub - SciML/LabelledArrays.jl: Arrays which also have a label for each element for easy scientific machine learning (SciML) ) rather than your own struct.

Legend! - just what I needed import StaticArrays.FieldVector struct Point3D <: FieldVector{3, Float64} x::Float64 y::Float64 z::Float64 end A = Point3D(1,2,3) A *= 2 A.z

This is a “technique” I’ve seen used in some library function to override a group of functions. import Base.*, Base.+,Base.-,Base./ struct X a::Float64 b::Float64 c::Float64 end X(x::Vector)=X(x...) ((;a,b,c)::X)() = [a,b,c] julia> for o in (:*,:+,:-,:/) @eval $o(y::Number…

[image] rocco_sprmnt21: The main reason for my post (rather than suggesting an alternative solution to those already provided) is to ask for enlightenment on the logic of the expression ((;a,b,c)::X)() = [a,b,c] I understand how it is used operationally but I would like to understand the meani…

Broadcast over struct fields?

General Usage

rocco_sprmnt21 July 10, 2023, 9:54am 13

Thank you very much.
I add some links related to the many ways to define methods of functions.

many way to define a function discussion
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Broadcast over struct fields?

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