Pout[:, 3:5] = X[:, 3:5]

for i in 1:3

PF_coe = Param_5[2 + i]

for j in 1:120

Qout[j, 2 + i] = Pout[j, 2 + i] * PF_coe

end

end

Not understand why it keeps resulting in the boundserror, I did not find where it is wrong. Could anyone help me to solve this problem?

Julia is column major, the first index is the column index:

```
julia> a = [1; 2; 3;;]
3Ă—1 Matrix{Int64}:
1
2
3
julia> a[1,3]
ERROR: BoundsError: attempt to access 3Ă—1 Matrix{Int64} at index [1, 3]
Stacktrace:
[1] getindex(::Matrix{Int64}, ::Int64, ::Int64)
@ Base ./essentials.jl:14
[2] top-level scope
@ REPL[3]:1
julia> a[3,1]
3
```

I agree that the problem seems to be that

```
Qout[j, 2 + i] = Pout[j, 2 + i] * PF_coe
```

should be

```
Qout[2 + i, j] = Pout[2 + i, j] * PF_coe
```

But this:

is unrelated. The first index is the *row* index in both column major and row major languages.

I think itâ€™s considerably more likely that `Qout`

doesnâ€™t have enough columns on construction and that this code is ported from Matlab where indexing out of bounds on the left hand side magically adds columns.

```
octave:1> q = zeros(120, 1);
octave:2> q(1, 3) = 1;
octave:3> size(q)
ans =
120 3
```

```
julia> q = zeros(120, 1);
julia> q[1, 3] = 1
ERROR: BoundsError: attempt to access 120Ă—1 Matrix{Float64} at index [1, 3]
```

Itâ€™s a difference in perspective - I take the first index to mean â€śwhich column should I look at?â€ť, while you take it to mean â€śwhich element of the row should I look at?â€ť. I.e., what I called â€ścolumn indexâ€ť is the â€śindex of the column in the rowâ€ť. From my POV, the second index gives me the row of a column, and the first index gives me the column in a table.

Thatâ€™s also a good point - perhaps @Xiaoting_Wang can clarify?

No, I take the first index to mean which *row* to look at. And so do you, I suspect, youâ€™re just mixing it up at the moment.

But my main point was that row major and column major languages have precisely the same meaning for the order of indices. The only difference is the memory layout, which is not visible to the user.

Youâ€™re right, in that message I was mixing things up - I was thinking of â€śwhich element in the columnâ€ť (i.e., the index into the column), not â€śwhich columnâ€ť!