Behavior of cd() in Julia script

[ZZP12]

Hi, I have a Julia script as below:

    generate_default_project("./default1")
    make_julia_model("./default1/Network.vff", "./default2")

    println(pwd())
    cd("./default2/")
    println(pwd())
    println("run the model")
    include("default2/Static.jl") 

The 1st line creates a folder ./default1, and the 2nd line generates some Julia scripts and puts them under folder ./default2.
The output from the 1st println(pwd()) is the absolute path of ./, and the 2nd one is of ./default2.
My question is on the last line. Here Static.jl is a script under ./default2, and the 2nd println(pwd()) indicates that the cwd is ./default2.
But if I tried include("./Static.jl"), it just does not work.
Can anyone explain what is happening here? Thanks much!
I am using Julia1.5 on Ubuntu 18.04.

[oheil]

You may find this discussion helpfull:

Include command inconsistent with isfile result

I am having trouble to include a file. More precisely isfile(fi) returns true, but include(fi) errors ERROR: LoadError: could not open file C:\temp\a\SomePackage\src\src\file.jl I created an MWE here. I simply run julia --startup-file=no --track-allocation=user mwe_include_error.jl in PowerShell (from the src directory) Is this expected not to work? It is quite irritating that isfile returns true, but the include command fails.

In short, quoted from @Tamas_Papp

@Tamas_Papp

include operates relative to @__DIR__ , which has nothing to do with the “current directory”

[giordano]

To elaborate on what @oheil said above, it’s always best to pass to include absolute paths, and also use joinpath to write paths, which takes care of different path separators across different operating systems.

[ZZP12]

Thanks! This is very helpful!