The only way I found to access multiple values of a dictionary is: get.(dictionary, ["a", "b", "c"], 0) I propose the following syntax: dictionary.["a", "b", "c"]

https://github.com/JuliaLang/julia/issues/19169 There are two fairly compelling potential meanings of x.[y]. It’s not yet clear which one is a better choice, and we’re not really considering adding new features until 1.0 is well out the door.

You could also broadcast getindex if you don’t need a default: julia> dictionary = Dict(:a => 1, :b => 2, :c => 3, :d => 4) Dict{Symbol,Int32} with 4 entries: :d => 4 :a => 1 :b => 2 :c => 3 julia> get.(dictionary, [:a, :b, :c, :e], 0) 4-element Array{Int32,1}: 1 2 3 0 julia> @which d…

Or do something like: julia> macro get(indexing) indexing.head ≠ :. && error("syntax: expected: `d.[ks...]`.") dict = indexing.args[1] indexing.args[1] = :getindex indexing.args[2].head = :tuple unshift!(indexing.args[2].args, dict) …

unshift! wasn’t defined. So I recreated the funciton like this: macro get(indexing) indexing.head ≠ :. && error("syntax: expected: `d.[ks...]`.") dict = indexing.args[1] indexing.args[1] = :getindex indexing.args[2].head = :tuple indexing.args[2].args = [Expr(:tuple, dict); indexing.args[2].ar…

Accessing multiple values of a dictionary

General Usage

mroavi March 10, 2021, 11:24am 5

These examples don’t seem to work in Julia 1.5. See How can I access multiple values of a dictionary using a tuple of keys? for a fix.

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Accessing multiple values of a dictionary

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