Will my variable be modified in a `do` block? Very subtle to anticipate

[WalterMadelim]

@sgaure

put code in functions

Thanks, I take your point.

---

(Update)

@sgaure

fun() do
    a = 14
end

is semantically equivalent to

function someuniquename() 
    a = 14
end
fun(someuniquename)

Now I have owned a deeper understanding. Therefore share my opinion:

The problem with do syntax is that it has an underlying unintuitive implication

• passing the function defined in do block as the first argument

Therefore the odds are that

@sgaure

the do-block is never executed.

But in sheer appearance,

fun() do
    a = 14
end

seems to suggest that a = 14 is done at that line.

I browsed some discussions and find that there are also people who don’t get used to using do block. e.g. here.

So we can write

local function af()
    a = 14
end
fun(af)

in place of any do syntax.