# Why Julia is giving a different answer than r?
**URL:** https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918
**Category:** New to Julia
**Tags:** question, broadcasting
**Created:** [May 16, 2023, 8:48am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918 "2023-05-16T08:48:59Z")
**Posts on this page:** 6
**Page:** 1
### Author:  [@Sahil\_Khan](https://discourse.julialang.org/u/Sahil_Khan)
#### Post date: [May 16, 2023, 8:48am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918/1 "2023-05-16T08:48:59Z")
i have a simple equation as given below (julia code). I’m getting different answer as compare to r. Am I missing something?
```julia
x=100
y=0
d = 20
h = -2
c = [0, 1, 2, 3, 4, 5]
A = x .+ ((y - x) / (1 .+ (c / d).^h))
```
answer in r : 100.00000 99.75062 99.00990 97.79951 96.15385 94.11765
answer in julia: NaN 100.0 100.0 100.0 100.0 100.0
---
### Author:  [@jishnub](https://discourse.julialang.org/u/jishnub)
#### Post date: [May 16, 2023, 8:51am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918/2 "2023-05-16T08:51:50Z")
The code that you’ve presented isn’t runnable. I’ve fixed it here, and the answer seems to match that from R:
```julia
julia> x=100;
julia> y=0;
julia> d = 20;
julia> h = -2;
julia> c = [0, 1, 2, 3, 4, 5];
julia> A = x .+ ((y - x) ./ (1 .+ (c / d).^h))
6-element Vector{Float64}:
100.0
99.75062344139651
99.00990099009901
97.79951100244499
96.15384615384616
94.11764705882354
```
---
### Author:  [@Elrod](https://discourse.julialang.org/u/Elrod)
#### Post date: [May 16, 2023, 8:53am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918/3 "2023-05-16T08:53:00Z")
I’d suggest using `@.` It makes it easier to avoid excess allocations, e.g. `c / d` should be `c ./ d`.
---
### Author:  [@jishnub](https://discourse.julialang.org/u/jishnub)
#### Post date: [May 16, 2023, 8:54am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918/4 "2023-05-16T08:54:25Z")
I agree, this is often better:
```julia
julia> A = @. x + ((y - x) / (1 + (c / d)^h))
6-element Vector{Float64}:
100.0
99.75062344139651
99.00990099009901
97.79951100244499
96.15384615384616
94.11764705882354
```
---
### Author:  [@Sahil\_Khan](https://discourse.julialang.org/u/Sahil_Khan)
#### Post date: [May 16, 2023, 9:00am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918/5 "2023-05-16T09:00:15Z")
Thanks a lot for help and suggestions. 🙂
---
### Author:  [@sijo](https://discourse.julialang.org/u/sijo)
#### Post date: [May 16, 2023, 9:30am UTC](https://discourse.julialang.org/t/why-julia-is-giving-a-different-answer-than-r/98918/6 "2023-05-16T09:30:19Z")
> [@jishnub](#):
>
> The code that you’ve presented isn’t runnable.
The original code with the missing dot runs on Julia 1.8 but the `number/vector` method was removed in 1.9: [Remove number / vector by antoine-levitt · Pull Request #44358 · JuliaLang/julia · GitHub](https://github.com/JuliaLang/julia/pull/44358) precisely to avoid this type of mistake 🙂