Why does Array{Int}() product Array{Int, 0} and not Array{Int, 1}

New to Julia
20

It’s useful as a type stable default argument value. Assuming for a moment that Array{T, N}() would create an empty array.

function f(x::Array{T, N}, weight = Array{T, N}()) where {T, N}
    if isempty(weight)
        # Compute unweighted special case.
    else
        # Compute the general case.
    end
end

Yes, you could use nothing to indicate no weight and being a small union it would probably be fast, but full type stability is still an attractive property.