Using SymPy.jl inside a module

after trial-and-errors, putting the following inside a module works:

import SymPy

### instead of:
# const sympy = SymPy.sympy    

### use the following:
import PyCall
const sympy = PyCall.PyNULL()
function __init__()
    copy!(sympy, PyCall.pyimport_conda("sympy", "sympy"))
end