# Using LsqFit to make a line using a model

**URL:** https://discourse.julialang.org/t/using-lsqfit-to-make-a-line-using-a-model/76321
**Category:** New to Julia
**Tags:** plotting, linear-regression
**Created:** [February 12, 2022, 11:03pm UTC](https://discourse.julialang.org/t/using-lsqfit-to-make-a-line-using-a-model/76321 "2022-02-12T23:03:37Z")
**Posts on this page:** 1
**Page:** 1

<div class="post-metadata">

### Author: ![Shamil-Luqman](https://sea2.discourse-cdn.com/julialang/user_avatar/discourse.julialang.org/shamil-luqman/32/33759_2.png) [@Shamil-Luqman](https://discourse.julialang.org/u/Shamil-Luqman)
#### Post date: [February 12, 2022, 11:03pm UTC](https://discourse.julialang.org/t/using-lsqfit-to-make-a-line-using-a-model/76321/1 "2022-02-12T23:03:37Z")

</div>

“”"  
@. model(x, p) = (p[1] + p[2]\*x) + (p[3]/(p[5]_√(2_π) ))_exp(-(x-p[4])^2/(2_p[5]^2))  
end  
“”"  
I have to fit this data into a steppere line graph I have and I can’t figure out how to use LsqFit to integrate the data.