# Use of interpolation function in ode model written in R/diffeqr
**URL:** https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046
**Category:** New to Julia
**Tags:** diffeq, interpolations
**Created:** [April 26, 2021, 5:35pm UTC](https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046 "2021-04-26T17:35:01Z")
**Posts on this page:** 5
**Page:** 1
### Author:  [@fkrauer](https://discourse.julialang.org/u/fkrauer)
#### Post date: [April 26, 2021, 5:35pm UTC](https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046/1 "2021-04-26T17:35:02Z")
Hi all
I am using Julia’s diffeq through R (diffeqr library) for the simulation of a simple SIR ode model. I want to interpolate a parameter value from the time in the ode model. I can set up a julia ODE model and call through R with the diffeqr library. However, I am not sure how to pass the interpolation function to the ODE? The instructions for julia suggest that any function can be introduced through the “parameter” argument of the ODE. How does this work if I call the function in R?
Below is my unsuccessfull attempt.
1. julia code for the model (“juliatoymodel.jl”):
```julia
function model(dxdt, init , param , time)
beta, gamma, mu, sigma, eta, phi = param[1]
interpolate = param[2]
S,I,R = init
N = S + I + R
i = interpolate(time)
beta_eff = i*beta * (1.0+eta*sin(2.0*pi*(time-phi)/365.0))
FOI = beta_eff*I/N
dxdt[1] = -FOI*S + mu*N - mu*S + sigma*R
dxdt[2] = FOI*S - gamma*I - mu*I
dxdt[3] = gamma*I - mu*R - sigma*R
end
```
1. R code that calls the functions:
```julia
library(diffeqr)
library(JuliaCall)
# params
maxtime <- 3650.0
beta <- 0.25
gamma <- 1/5
mu <- 1/(70*365)
sigma <- 1/365
eta <- 0.2
phi <- 10
theta <- c(beta, gamma, mu, sigma, eta, phi)
# init
init <- c(9999, 1, 0)
# setup environment
enviro <- diffeqr::diffeq_setup()
julia_source("juliatoymodel.jl")
# interpolation function
julia_library("Interpolations")
julia_assign("in", c(0,365,730,1095,1460,1816,2181,2546,2911,3276,3650))
julia_assign("out", c(1,1,1,1,0.9,0.8,0.7,0.8,0.9,1,1))
julia_assign("init", init)
julia_assign("param", list(theta, julia_command("interpolate = LinearInterpolation(in,out);")))
julia_assign("time", c(0.0, maxtime))
problem = julia_eval("ODEProblem(model, init, time, param)")
solution = enviro$solve(problem, enviro$AutoVern7(enviro$KenCarp4()),
saveat=7.0, abstol=1e-8, reltol=1e-6)
```
I have tried to make an R list with [[1]] params and [[2]] the interpolation function, which is assigned to a Julia object “param”. Unfortunately this throws an error
```julia
Error: Error happens in Julia.
MethodError: objects of type Nothing are not callable
```
because ` julia_command("interpolate = LinearInterpolation(in,out);")` returns NULL somehow. How can I pass the interpolation function correctly? I am looking for an R/JuliaCall solution, not a pure Julia solution. Thanks a lot
Bw, Fabienne
---
### Author:  [@Non-Contradiction](https://discourse.julialang.org/u/Non-Contradiction)
#### Post date: [April 26, 2021, 7:35pm UTC](https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046/2 "2021-04-26T19:35:29Z")
You can try to use the `julia_eval` function, which will return the result from julia to R. The `julia_command` function will not return the result from julia to R, so the implicit result is always `NULL`.
---
### Author:  [@fkrauer](https://discourse.julialang.org/u/fkrauer)
#### Post date: [April 26, 2021, 8:37pm UTC](https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046/3 "2021-04-26T20:37:59Z")
Thanks a lot for the fast reply. I tried `julia_eval`, but it throws an error:
```julia
Error: Error happens in Julia.
MethodError: objects of type Array{Float64,1} are not callable
Use square brackets [] for indexing an Array.
```
Also, `julia_eval("param")` returns the result of the function (the interpolation), instead of the function itself. So the main question, how to pass the function itself to the Julia ODE model (within the parameter argument), is still unresolved.
---
### Author:  [@Non-Contradiction](https://discourse.julialang.org/u/Non-Contradiction)
#### Post date: [April 26, 2021, 9:04pm UTC](https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046/4 "2021-04-26T21:04:53Z")
I’m not very familiar with the diffeq ecosystem, and not sure what should be provided as the argument.
But `julia_assign` will convert any R object into julia object (including R functions to julia functions) and give it a name, and `julia_eval` will try to convert any julia object to R object (including julia functions to R functions).
And we need to pay attention to julia callable object (I’m not sure whether it is involved in the question). Because JuliaCall sees the callable object not as a function, so it will not turn it into R function. (Because in R, there is no such thing as callable object.)
But you can always construct a julia function based on the callable object
So suppose `interpolate` is a callable object, you can do `julia_eval("x -> interpolate(x)")` to get a function back into R.
---
### Author:  [@fkrauer](https://discourse.julialang.org/u/fkrauer)
#### Post date: [April 27, 2021, 12:20pm UTC](https://discourse.julialang.org/t/use-of-interpolation-function-in-ode-model-written-in-r-diffeqr/60046/5 "2021-04-27T12:20:51Z")
thanks. I have run the same script, but without explicitly including the interpolation function in the parameter argument of the ODE, and it seems to work. I guess as long as the interpolation function is defined in the julia universe, it can be called even if it is outside the ODE function. There may be a better solution for this, but it seems to work for now.