Syntax of exchanging values of 2 variables seems to be broken in short-circuit evaluation

General Usage
4

This is because of named tuple syntax.

Notice (t1, t2 = (t2, t1)) is short for (t1 = t1, t2 = (t2, t1)) and results in NamedTuple{(:t1, :t2)}((t1, (t2, t1))).

So you’ll need to disambiguate a (named) tuple literal from a ()-grouped expression. You could do this like so:

true && ((t1, t2) = (t2, t1)) # an expression, not a tuple, since no comma

true && begin # explicit block
    t1, t2 = t2, t1
end

So this isn’t a bug — just confusion about Julia’s (very carefully designed) syntax!

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