Subset differences between || and | operators

New to Julia
2

This doesn’t mean what you think: the | operator has lower precedence than !=, so your expression is equivalent to a != (0 | b) != 0.

And since 0 | b is just b for any integer b, this means that what you have is effectively a != b != 0.

What do you mean? I get:

julia> subset(df , [:x, :y] => ByRow((a,b)-> a !=0 || b !=0))
3×4 DataFrame
 Row │ x      y      z       w      
     │ Int64  Int64  String  String 
─────┼──────────────────────────────
   1 │     2      0  A       A
   2 │     8      0  C       B
   3 │     9      8  D       B

which looks correct to me.

It sounds like what you want is a != 0 && b != 0, not ||?

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