Ah I see.
Setup:
julia> df = DataFrame(a = [1, 2, 3, 4]); df2 = DataFrame(a2 = [1, 2]);
Indexing solution:
julia> df[in.(df.a, Ref(df2.a2)), :]
2×1 DataFrame
Row │ a
│ Int64
─────┼───────
1 │ 1
2 │ 2
filter
solution
julia> filter(:a => in(df2.a2), df)
DataFramesMeta solution
julia> @where(df, in.(:a, Ref(df2.a2)))
2×1 DataFrame
Row │ a
│ Int64
─────┼───────
1 │ 1
2 │ 2
Note: Performance is actually better if you convert df2.a2
to a Set
first, but you don’t have to worry about this if things are fast enough.
Also I think this requires Julia 1.5 or above.