Thank you for any help with this. When I convert this string to Date I get the below format. What am I doing wrong? Why can’t I get “yyyy-mm-dd”? Thank you! using Dates, DataFrames id = [1, 2, 3, 4, 5] bday = [“8/23/62”, “12/26/66”, “1/17/62”, “12/30/61”, “12/13/62”] df = DataFrame(id=id, bday=…

Probably because 62 is parsed as year 62. You can do this (I skipped the df part) Date.(bday, "mm/dd/yy") .+ Year(1900)

Thanks, it works but for dates that are > 12/31/1999.

This was useful. Sorry that I did not find it before posting the question. [image] Parsing a CSV file with 2-digit year New to Julia I have a file with dates formatted like this: 5/7/10 2:11 for the date 2010-5-7 and the time 2:11 am. I’m having the hardest time getting…

Were there no long lasting lessons learned from dealing with this issue so much 20+ years ago?

String to Date

New to Julia

gjh April 20, 2022, 4:13pm 4

This was useful. Sorry that I did not find it before posting the question.

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String to Date

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