Hi ! I’ve encountered something curious, and here is a minimal example :slight_smile: function f(x::UInt,y::UInt)::UInt x + y end And now i want to do f(2,2) but julia says this to me : julia> f(2,2) ERROR: MethodError: no method matching f(::Int64, ::Int64) Stacktrace: [1] top-level scope…

[image] lhp22: but UInt8 <: UInt is true, isn’t it ? Try it out: julia> UInt8 <: UInt false Maybe you are looking for Unsigned instead? That’s the supertype of all unsigned integers: julia> UInt8 <: Unsigned true Now even if you define f(x::Unsigned, y::Unsigned) this will still not allow…

[SOLVED] UInt is not Int!

New to Julia

lhp22 May 23, 2020, 8:50pm 7

Because I have a complex type system ? It should be unnice if I couldn’t use it for easing my code

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[SOLVED] UInt is not Int!

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