# Simplify an equality

**URL:** <https://discourse.julialang.org/t/simplify-an-equality/66562>\
**Category:** New to Julia\
**Tags:** question, symbolic, sympy\
**Created:** [August 17, 2021, 5:54pm UTC](https://discourse.julialang.org/t/simplify-an-equality/66562 "2021-08-17T17:54:16Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![fms-1988](https://sea2.discourse-cdn.com/julialang/user_avatar/discourse.julialang.org/fms-1988/32/20275_2.png) [@fms-1988](https://discourse.julialang.org/u/fms-1988)\
**Post date:** [August 17, 2021, 5:54pm UTC](https://discourse.julialang.org/t/simplify-an-equality/66562/1 "2021-08-17T17:54:17Z")

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I have the following equality: \frac{x+y}{a}=0  
I want to simplify this equality, ie: x = -y  
I’m trying the following code, but without success:

```julia
using SymPy
x,y,a = symbols("x,y,a") 
eq1 = Eq((x+y)/a,0)
simplify(eq1)

```

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<div class="post-metadata">

**Author:** ![j\_verzani](https://sea2.discourse-cdn.com/julialang/user_avatar/discourse.julialang.org/j_verzani/32/8551_2.png) [@j\_verzani](https://discourse.julialang.org/u/j_verzani)\
**Post date:** [August 17, 2021, 6:42pm UTC](https://discourse.julialang.org/t/simplify-an-equality/66562/2 "2021-08-17T18:42:09Z")

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Maybe `solve(eq1)` or `solve(eq1,x)` works for this and other cases.
