Return a function defined in a function

New to Julia
2

It’s an unfortunate and long-standing bug. See: Confused by behaviour of nested functions for more discussion.

Fortunately, it’s easy to avoid by defining an anonymous function instead:

function fx(n)
  if n == 1
    f = x -> 2x
  else
    f = x -> 3x
  end
  f
end
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