Hi, For example as below, how can I get the result “123” without “abc, space, …etc.”, using regular expression? julia> replace("abc12 3abc ", r"\d+" => "") "abc abc " Technically, I can meet the aim via filter as below: julia> filter(isdigit, "abc12 3abc ") "123" Just wonder if I can do it vi…

Remove unmatched parts via regular expression

lbilli December 31, 2021, 5:28am 6

You can try:

julia> replace("abc12 3abc @-", r"[^\d]" => "")
"123"

3 Likes

Topic		Replies	Views
Removing characters from String General Usage strings	15	12591	January 26, 2021
Regular Expression Data	4	893	April 20, 2017
How to find and replace (Regx) in string abcdac only 'a' who is not before 'c'? General Usage	6	661	August 22, 2020
Regex: ERROR: PCRE error: requested value is not set New to Julia regex	4	652	May 9, 2020
Help me make a regex, instead of this? General Usage strings , regex	13	1382	May 5, 2019