I’m trying to plot 3D surface plot like the figure below (source: Wikipedia ): [512px-Rosenbrock_function.svg] Here is my attempt in julia; x = [-2:0.05:2;] y = [-1:0.05:3;] z = (1 .-x').^2 .+ 100 .*(y.-x'.^2).^2 minZ = minimum(z[:]); maxZ = maximum(z[:]); c = minZ .+ (maxZ-minZ).*log.(1 .+z…

You may get reasonably close with the following code (using Gnuplot.jl ): using Gnuplot x = [-2:0.05:2;] y = [-1:0.05:3;] z = (1 .-x').^2 .+ 100 .*(y.-x'.^2).^2 minZ = minimum(z[:]); maxZ = maximum(z[:]); c = minZ .+ (maxZ-minZ).*log.(1 .+z .- minZ) ./ log(1+maxZ-minZ) @gsp "set xyplane at 0…

Plotting in Julia like Matlab plots

General Usage

dpsanders August 15, 2020, 3:43pm 2

This recent post may be useful: