# Plotting by multiple factors
**URL:** https://discourse.julialang.org/t/plotting-by-multiple-factors/68237
**Category:** General Usage
**Tags:** question, plotting, dataframes, statsplots
**Created:** [September 15, 2021, 11:09pm UTC](https://discourse.julialang.org/t/plotting-by-multiple-factors/68237 "2021-09-15T23:09:23Z")
**Posts on this page:** 5
**Page:** 1
### Author:  [@Christopher\_Fisher](https://discourse.julialang.org/u/Christopher_Fisher)
#### Post date: [September 15, 2021, 11:09pm UTC](https://discourse.julialang.org/t/plotting-by-multiple-factors/68237/1 "2021-09-15T23:09:23Z")
Hi all,
I have a dataset with three factors and one dependent variable. In the example below, how do I get all of the linear data in the top plot and all of the exponential data in the bottom plot. I tried changing the order of variables in group, but to no avail.
**Example**
**Code**
```julia
using StatsPlots, DataFrames
linear(x, β0, β1) = β0 + β1 * x
exponential(x, β, λ) = β * exp(λ * x)
xs = 1:10
np1 = [(p1,p2,x,y = linear(x, p1, p2)) for p1 in [0.0,1.0] for p2 in [.2,.6] for x in xs]
df = DataFrame(np1)
df[!,:function] .= "linear"
np2 = [(p1,p2,x,y = exponential(x, p1, p2)) for p1 in [.0002,.0003] for p2 in [1.0,1.1] for x in xs]
temp = DataFrame(np2)
temp[!,:function] .= "exponential"
append!(df, temp)
@df df plot(:x, :y, group=(:p1,:p2,:function), layout=(2,1), ylims=(0,20))
```
---
### Author:  [@rafael.guerra](https://discourse.julialang.org/u/rafael.guerra)
#### Post date: [September 16, 2021, 8:57am UTC](https://discourse.julialang.org/t/plotting-by-multiple-factors/68237/3 "2021-09-16T08:57:41Z")
You can use grouped dataframes and loop over these.
As there are only two groups in your example, the code below writes it explicitly without a loop:
```julia
gdf = groupby(df, :function)
fig = plot(layout=(2,1), legend=:topleft)
@df gdf[1] plot!(fig[1],:x, :y, group=(:function, :p1, :p2), ylims=(0,20))
@df gdf[2] plot!(fig[2],:x, :y, group=(:function, :p1, :p2), ylims=(0,20))
```
---
### Author:  [@Christopher\_Fisher](https://discourse.julialang.org/u/Christopher_Fisher)
#### Post date: [September 16, 2021, 9:14am UTC](https://discourse.julialang.org/t/plotting-by-multiple-factors/68237/4 "2021-09-16T09:14:16Z")
Thank you for your solution. This is a good workaround.
I wonder if it would be possible to add a feature to StatsPlots that organizes the factors based on the layout and group arguments. I suppose it might be hard to generalize a pattern.
---
### Author:  [@rafael.guerra](https://discourse.julialang.org/u/rafael.guerra)
#### Post date: [September 16, 2021, 11:23am UTC](https://discourse.julialang.org/t/plotting-by-multiple-factors/68237/5 "2021-09-16T11:23:33Z")
Someone more knowledgeable should advise.
At any rate, do not see harm in opening an [issue at StatsPlots.jl,](https://github.com/JuliaPlots/StatsPlots.jl/issues) in case there is really one and improvements can be made as you suggest.
---
### Author:  [@Christopher\_Fisher](https://discourse.julialang.org/u/Christopher_Fisher)
#### Post date: [September 16, 2021, 11:42am UTC](https://discourse.julialang.org/t/plotting-by-multiple-factors/68237/6 "2021-09-16T11:42:25Z")
I opened an [issue](https://github.com/JuliaPlots/StatsPlots.jl/issues/466). Thanks again for your help!