# Plot using @timed
**URL:** https://discourse.julialang.org/t/plot-using-timed/37714
**Category:** General Usage
**Tags:** question
**Created:** [April 16, 2020, 8:56pm UTC](https://discourse.julialang.org/t/plot-using-timed/37714 "2020-04-16T20:56:06Z")
**Posts on this page:** 4
**Page:** 1
### Author:  [@A.U.M](https://discourse.julialang.org/u/A.U.M)
#### Post date: [April 16, 2020, 8:56pm UTC](https://discourse.julialang.org/t/plot-using-timed/37714/1 "2020-04-16T20:56:06Z")
I have implemented three functions to calculate the Fibonacci numbers like the following:
```julia
function fib(n::Integer)::BigInt
if n <= 1
n
else
fib(n-1) + fib(n-2)
end
end
```
\*\*
```julia
fib2(n::Integer)::BigInt =round(BigInt,((1+sqrt(BigFloat(5)))/2)^n / sqrt(BigFloat(5)))
```
\*\*
```julia
global cache = Dict{BigInt, BigInt}(0 => 0, 1 => 1)
function fib3(n::Integer)
global cache
if haskey(cache, n)
cache[n]
else
cache[n] = fib3(n-1) + fib3(n-2)
end
end
```
\*\*
How can I use the macro @timed to plot the time and memory consumption of the
various functions to calculate Fibonacci numbers? I will be appreciated if someone can give me an example according to my code.
Updates :
I tried to do something like this
```julia
x=[1:3]
fib=[fib(5),fib2(5),fib3(5)]
y= [@timed fib[i] for i = 1:3]
using Plots
plot(x,y)
```
but it dosen’t work and i think the problem is how to handel ( plot ) in my case
---
### Author:  [@pixel27](https://discourse.julialang.org/u/pixel27)
#### Post date: [April 16, 2020, 9:58pm UTC](https://discourse.julialang.org/t/plot-using-timed/37714/2 "2020-04-16T21:58:00Z")
Didn’t you ask that already here? [How to access the data in @timed and plot directly](https://discourse.julialang.org/t/how-to-access-the-data-in-timed-and-plot-directly/37692)
First you have an issue, you declare a function fib then declare fib as an array…so things go weird. If I rename your function to `fib1` things work better…
This might not be the most elegant way of doing this but:
```julia
function record(f, a)
val, time, bytes, gctime, memallocs = @timed f(a)
(time=time, bytes=bytes, gctime=gctime, memallocs=memallocs)
end
x=[1:3]
fib=[fib1, fib2, fib3]
y= [record(fib[i], 10).time for i = 1:3]
using Plots
plot(x,y)
```
If you want bytes you can change .time to .bytes when setting Y.
---
### Author:  [@A.U.M](https://discourse.julialang.org/u/A.U.M)
#### Post date: [April 16, 2020, 10:37pm UTC](https://discourse.julialang.org/t/plot-using-timed/37714/3 "2020-04-16T22:37:32Z")
Thank you for your reply.I want to summary what i understood from your code.
first you generate a function called " record " to store the output data of @timed like ( value , time , bytes …etc ) so i can’t access the output data directly from @timed ?
and after this in the following line you just evaluate the time of fib1(10) , fib2(10) , fib3(10)
`y= [record(fib[i], 10).time for i = 1:3]`
Is there a way to change the values on the x-axis from [1:3] to be string ? like Fib1 , Fib2…etc?
---
### Author:  [@pixel27](https://discourse.julialang.org/u/pixel27)
#### Post date: [April 16, 2020, 10:48pm UTC](https://discourse.julialang.org/t/plot-using-timed/37714/4 "2020-04-16T22:48:40Z")
> [@A.U.M](#):
>
> so i can’t access the output data directly from @timed
I’m not an expert at Julia you might be able to do `(@timed fib1(5))[2]` maybe? Granted you’ll have to remember what [2] is, or [3] is. `@timed fib1(5)[2]` probably won’t work since that will try to take the 2nd returnvalue from fib1 I believe…
> [@A.U.M](#):
>
> Is there a way to change the values on the x-axis from [1:3] to be string ? like Fib1 , Fib2…etc?
Probably, you would need to check the Plots documentation, I’m not an expert at that either. 🙂
Another thing to note with your original code:
```julia
fib=[fib(5),fib2(5),fib3(5)]
```
Actually creates an array of 3 items, with the return value of the functions…the functions are executed at that point, not later when you referenced them. So if your @timed had worked it would return the amount of time to access the array element…
```julia
fib=[fib1, fib2, fib3]
y= [(@timed fib[i](5))[2] for i = 1:3]
```
might work more like your original code desired.