You can also sort the columns and re-assemble:
julia> A = randn(2,5);
julia> reduce(hcat, sort(eachcol(A); by=norm))
2×5 Matrix{Float64}:
-0.111708 -1.31249 -1.49302 1.11223 0.730328
0.684414 0.589954 -0.115788 -1.068 -1.93679
julia> ans == A[:, sortperm(norm.(eachcol(A)))]
true
Edit: or better, use sortslices which takes the same keyword:
julia> sortslices(A, dims=2, by=norm)
2×5 Matrix{Float64}:
-0.111708 -1.31249 -1.49302 1.11223 0.730328
0.684414 0.589954 -0.115788 -1.068 -1.93679