Hi, based on this f = x -> x^2 f(10) I’d like to develop a function with two inputs f1(a,b) = a,b -> a^2+b f1(2,1) but this returns (2, λ). What are the meaning of lambda returned here and the right syntax for this?

λ refers to the anonymous function b->a^2+b Simply do f1(a,b) = a^2+b

This also works if you want an anonymous function rather than a generic function. julia> f1 = (a, b) -> a^2 + b #3 (generic function with 1 method) julia> f1(2, 1) 5

Oh I see julia> f1(a,b) = a^2 + b f1 (generic function with 1 method) julia> f2 = (a, b) → a^2 + b #44 (generic function with 1 method) But what is anonymous function used for? This seems not to be explained in its documentation https://docs.julialang.org/en/v1/manual/functions/#man-anonymo…

Just a little explanation, if you are curious. The code gets interpeted as f1(a, b) = a, (b -> a^2+b) which gets interpreted as f1(a, b) = return a, (b -> a^2+b) which produces the obvious error.

“Anonymous” literally means “without a name” and you use them whenever your function might not merit being named. For example, if I want to add 1.3 to each item of a list, defining add1point3(x) might seem a bit silly. So I can instead say map(x -> x + 1.3, list) and avoiding giving that operation a…

[image] 1634: But what is anonymous function used for ? If you have a function that takes a function as an argument, it can more concise to define an anonymous function right in the outer function argument list. A trivial example: julia> d = rand(10) 10-element Array{Float64,1}: 0.35512475…

There may be an implicit doubt in @1634 ’s question that remains to be answered: Ok, anonymous functions can be used as “throw-away functions” in arguments for map, findfirst, etc., without ever giving them a name. But what’s the difference between a “named” function and an anonymous one when it is …

[image] heliosdrm: I can’t define methods for different number of types of arguments. (If someone else does know how to do it, just excuse my ignorance!) There is no explicit syntax AFAIK, but one could easily get around this by defining a macro that converts @multianon begin (a::Int, b:…

Can’t you do foo = x -> … (::typeof(foo))(x, y) = … ?

One-line function return lambda__anonymous function

New to Julia

zdenek_hurak June 5, 2021, 10:10pm 11

Yes: Documentation about using anonymous and named functions with pmap - #3 by baggepinnen

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One-line function return lambda__anonymous function

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