Hi, what is the Julia-way of obtaining off-diagonal elements of a matrix flattend as a vector, e.g. A = [1 2; 3 4] offdiag(A) = [2, 3] I stumbled across diagind but could not figure out how to do it neatly. Best, jamblejoe EDIT: Better example: A = [1 2 3; 4 5 6; 7 8 9] offdia(A) = [2, 3, 4, …

Or using the generalized indexing accessors, function offdiag2(A::AbstractMatrix) [A[ι] for ι in CartesianIndices(A) if ι[1] ≠ ι[2]] end which should work for indexes other than 1-based.

Off diagonal elements of Matrix

General Usage

jamblejoe June 10, 2020, 11:12pm 5

No, I mean Array{T, 2}.

Topic		Replies	Views
How to get a matrix anti-diagonal? New to Julia question , linearalgebra	6	674	August 25, 2023
How to query elements in a matrix diagonal to a given point Numerics linearalgebra	8	5960	May 11, 2020
Vectorized variable assignment (assign matrix off diagonal values) New to Julia linearalgebra	4	2083	October 17, 2018
Efficiently remove diagonal from Array General Usage	9	1604	April 20, 2020
Initializing a number matrix General Usage	19	1087	April 10, 2018

Off diagonal elements of Matrix

Related topics