Hi, I’m relatively new to Julia. Here’s a thing that puzzles me. If you have a simple overloaded function like this: function a( x :: Float64 ) print( "Float version" ) end function a( x :: Integer ) print( "Integer version" ) end it works exactly as you’d expect. But if you hav…

Named parameters with type overloads

Tamas_Papp December 31, 2018, 1:49pm 6

Sorry, I am not getting what the problem is: whether the function gets called depends on the code using it. Eg

b()

would call it.

Can you clarify what the “it” refers to in the sentence? Multiple dispatch? Or how keyword arguments behave?

Did you read the section I linked?

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