leaq(a,b) = (a <= b) || (a ≈ b) leaq(a,b,c) = leaq(a,b) && leaq(b,c) Is there a better way of doing this? The only alternative I can think of is to subtract some epsilon from the lesser part of the inequality based on machine precision? I feel like it should be in Base, but I’m sure there’s a good…

[image] anon92994695: It would be pretty awesome to be able to make functions from 2 or more symbols. I ran into this when I was trying to do approximate greater than and approximate lesser than functions Why not use ≲ and ≳ or ⪅ and ⪆, which are all valid infix comparison operators in Julia…

Less than approx equals? <≈

New to Julia

ericphanson August 24, 2020, 12:28am 4

I saw GitHub - lairez/ExactPredicates.jl: Fast and exact geometrical predicates in the Euclidean plane awhile ago which seems like it might be of interest to you

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Less than approx equals? <≈

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