I am trying to understand how to create a sparse matrix in Julialang. The example project that I am learning in GitHub, I spotted spzeros() function which I believe it is going to create a sparse matrix. When I test following lines in Julialang terminal, it gave me error. A = spzeros(20,0) println…

Is spzeros deprecated for creating sparse matrix in Julialang?

Elrod January 19, 2021, 5:41am 6

He meant

julia> using SparseArrays

julia> A = spzeros(20,0)
20×0 SparseMatrixCSC{Float64, Int64} with 0 stored entries

3 Likes

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