Is it possible to splat into ccall?

[lmtzx9h4qqnt]

No, that’s all understood. For some reason, I just got the idea at some point that @ccall defers to ccall (instead of making an Expr(:foreigncall) directly). Perhaps because of statements like these:

@c42f

@ccall is a more recent and much more attractive syntax for the same thing which doesn’t need special support from the parser or lowering.

@Sukera

Like I said, @ccall is the same as ccall, just in macro form.

But they’re not the same! @ccall can call varargs functions with arbitrary (mixed) types, whereas varargs arguments must all be of the same type with ccall. These are equivalent:

julia> ccall(:printf, Cint, (Cstring, Cint...), "%d %d %d\n", 1, 2, 3);
1 2 3

julia> @ccall printf("%d %d %d\n"::Cstring; 1::Cint, 2::Cint, 3::Cint)::Cint;
1 2 3

But there’s no way to express the following using ccall:

julia> @ccall printf("%d %f %s\n"::Cstring; 1::Cint, 2.0::Cdouble, "abc"::Cstring)::Cint;
1 2.000000 abc

(This is also stated in the documentation.)

Edited to add: I just realized there does seem to be one thing that ccall can do and @ccall can’t, which is specifying a calling convention? (Seems to be hard-coded to :ccall, if I understand the code correctly.) Should be straightforward to add, but it’s not in the current implementation.