How to "source" a string?

New to Julia
11

One solution that I don’t think has been mentioned yet: using higher-order functions (HOF). In my experience, it is frequently the case that most of the code can be factored out, and only a small part of it needs to change. It can then be beneficial to factor out the large, common parts in a higher-order function; the small, “extra” part can then be passed as a function argument to the HOF.

Minimal example:

# A higher-order function  to factor out all common code
julia> function common_parts(extra, x, y)
           z = 2x + y    # block A
           z = extra(z)  # extra block
           z *= 3        # block B
       end
common_parts (generic function with 1 method)

# No extra part: z = identity(z)
julia> fun(x, y) = common_parts(identity, x, y)
fun (generic function with 1 method)

# I tend to like the `do` block better, but you could also write
# gun(x, y) = common_parts(z -> z-5, x, y)
julia> gun(x, y) = common_parts(x, y) do z
           z - 5
       end
gun (generic function with 1 method)

julia> fun(1, 2)
12

julia> gun(1, 2)
-3
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