Hello, good afternoon How to solve inequalities of this kind? 4 <= 3x - 2 < 13

For completeness, within Julia, the same can be done with SymPy as: @syms x::real u = solve(Lt(4, 3x-2), x) & solve(3x-2 ≦ 12,x) # \leqq[tab] is infix unicode for Lt u.as_set() The latter conversion allows you to query, as in 3 ∈ u.as_set()

I saw it when searching for a solution, but it has not has two inequalities. Then I found something in Python group. x = sp.symbols('x') s1 = sp.solve_univariate_inequality(4 <= 3*x - 2, x) s2 = sp.solve_univariate_inequality(3*x - 2 < 13, x) s1 & s2

How to solve inequalities of this kind?

General Usage

empet March 21, 2023, 7:11pm 2

See this thread https://discourse.julialang.org/t/solving-inequations/58410.

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How to solve inequalities of this kind?

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