hi, everyone~ my code like this: function hello(;name="world") println("hello, $(name)") end keyname = "name" hello(keyname="today") # I don't want to use hello(name="today") directly~ then will get error: ERROR: LoadError: MethodError: no method matching hello(; keyname=“today”) Closest…

Eg, among other solutions, hello(;name="world") = println("hello, $(name)") keyname = "name" hello(; Dict( Symbol(keyname) => "today")...) # with a Dict hello(; NamedTuple{(Symbol(keyname), )}(("today", ))...) # with a NamedTuple but I concur with @JeffreySarnoff , this is not necessarily idiomatic…

That’s an usual question. It would help to know why you don’t want to use hello(name="today") directly. Keyword arguments (like name in hello(;name) are intended to be set by assigning to the keyword when the function is called (hello(name="today")). There is no language-level provision for dynam…

@JeffreySarnoff @Tamas_Papp thanks~ Originly I want to write a CLI package（like fire package of python https://github.com/google/python-fire ), then I guess maybe I should pass ARGS as keyword arguemnt of function which is fired.

thanks! The last line code with NamedTuple works ~ hello(; NamedTuple{(Symbol(keyname), )}(("today", ))...) # with a NamedTuple

Why not just hello(; Symbol(keyname) => "today") ?

@JeffreySarnoff @Tamas_Papp @tkoolen thanks for the kind help! I just wrote my first julia package in github( https://github.com/orangeSi/Jfire.jl ), it only support call Function from Module or Function directly yet, it is simple that need to go ahead~

How to set variable to key of keyword arguments of function?

General Usage

orange_si December 27, 2018, 2:21am 7

thanks a lot, the code works and is more cleaner ! I am a fresh bird of julia, give me some time to really understand this syntax.

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How to set variable to key of keyword arguments of function?

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