# How to round symbolic matrix

**URL:** <https://discourse.julialang.org/t/how-to-round-symbolic-matrix/86507>\
**Category:** General Usage\
**Tags:** symbolics, sympy\
**Created:** [August 29, 2022, 4:56pm UTC](https://discourse.julialang.org/t/how-to-round-symbolic-matrix/86507 "2022-08-29T16:56:33Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![Starpower\_Power](https://sea2.discourse-cdn.com/julialang/user_avatar/discourse.julialang.org/starpower_power/32/38282_2.png) [@Starpower\_Power](https://discourse.julialang.org/u/Starpower_Power)\
**Post date:** [August 29, 2022, 4:56pm UTC](https://discourse.julialang.org/t/how-to-round-symbolic-matrix/86507/1 "2022-08-29T16:56:33Z")

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![image_19](https://global.discourse-cdn.com/julialang/original/3X/7/5/75ada45993cc4e3db8ef5b393186f9a478d74885.png)

i want that output in round form  
for emp: 1e-17 =0 should be zero.  
thanks

---

<div class="post-metadata">

**Author:** ![qwerty](https://avatars.discourse-cdn.com/v4/letter/q/4491bb/32.png) [@qwerty](https://discourse.julialang.org/u/qwerty)\
**Post date:** [August 29, 2022, 5:44pm UTC](https://discourse.julialang.org/t/how-to-round-symbolic-matrix/86507/2 "2022-08-29T17:44:13Z")

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```julia
using SymPy
@syms t d
r = [cos(t) -sin(t) d;sin(t) cos(t) 0; 0 0 1]
[subs(i, (t, π)) for i in r]

```
