I understand that Julia doesn’t have “pointers” in the way that C++ does. However, I have stumbled upon an instance in which I feel like I really need something like a pointer that can refer to a variable from within a struct without actually copying that variable’s data into the struct itself. I wa…

Just make the Result mutable struct?.. btw the only thing that actually allocates are vector and matrix inside LinearProgram, but they are just references anyway: julia> struct LinearProgram c::Vector{Float64} end julia> struct LinearProgramResult lp::LinearProgram …

Thank you, this is what I needed. Is this the right way of thinking about what making the struct mutable does? Namely, a mutable struct is a struct in which references variables at construction time are encoded as references to those variables rather than copies?

No. Mutable structures are structrues where the individual properties can be rebinded to other objects. The mutability property is irrelevant here: a = [1,2,3] mutable struct Foo x::Array{Int64,1} end o = Foo(a) a[2] = 20 o # changed struct Goo x::Array{Int64,1} end o = Goo(a) a[2] = 200 o …

Probably the key point here is that, when referencing the LinearProgram struct inside LinearProgramResults, you may be copying only scalars and references, but not the complete arrays contained in the LinearProgram: julia> struct LinearProgram n::Int x::Vector{Float64} …

How to reference a variable within a struct

General Usage

Henrique_Becker February 10, 2022, 1:48pm 5

Maybe this will help you to form a mental model

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How to reference a variable within a struct

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