I have a function f() = (a=1, b=2, c=3) , and I can pick out one of the returned components of the tuple as julia> f().a 1 Can I select in this way a and at the same time c? In other words, I would like to get a, c = f()???.

Only works for Julia \geq 1.7 though

Actually, I realized I would really like to be able to collect the results in variables whose names are not the same as those in the named tuple. For example: myvar = f().c. But with an arbitrary multiple selection, myv1, myv2 = f()... (let us say, a and c). Can this be done?

OK, found this: julia> v1, v2 = f()[[:a, :c]] (a = 1, c = 3) …

julia> f() = (; a=1, b=2, c=3, d=4) f (generic function with 1 method) julia> x, _, _, y = f() (a = 1, b = 2, c = 3, d = 4) julia> x 1 julia> y 4

here there may be something close

Nice! What I’m not so happy about is that one has to know the order in which the arguments have been returned.

[image] PetrKryslUCSD: Can this be made more succinct? How do you want it to look? There’s not all that much unsuccinctness to work with in the solution you found.

How to pick out selected output components of a named tuple?

General Usage

Eben60 June 12, 2023, 7:29pm 9

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How to pick out selected output components of a named tuple?

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